Home
Class 11
PHYSICS
A body is to be projected vertically upw...

A body is to be projected vertically upwards from earth's surface to reach a height of `9R`, where `R` is the radius of earth. What is the velocity required to do so? Given `g=10ms^(-2)` and radius of earth`=6.4xx10^(6)m`.

Promotional Banner

Similar Questions

Explore conceptually related problems

If a body is to be projected vertically upwards from earth's surface to reach a height of 10R where R is the radius of earth. The velocity required to be si is

Calculate the velocity with which a body must be thrown vertically upward from the surface of the earth so that it may reach a height of 10R , where R is the radius of the earth and is equal to 6.4 xx 10^(6)m. (Given: Mass of the earth = 6 xx 10^(24) kg , gravitational constant G = 6.7 xx 10^(-11) N m^(2) kg^(-2) )

Calculate the velocity with which a body must be thrown vertically upward from the surface of the earth so that it may reach a height of 10R , where R is the radius of the earth and is equal to 6.4 xx 10^(6)m. (Given: Mass of the earth = 6 xx 10^(24) kg , gravitational constant G = 6.7 xx 10^(-11) N m^(2) kg^(-2) )

A body is projected vertically upwards from the earth's surface. The body reaches a height equal to one half of radius of earth. Calculate the initial speed with which the body was projected initially. Radius of earth = 6,400 km Mass of earth = 6 xx 10^(24) kg

The initial velocity v_(i) required to project a body vertically upward from the surface of the earth to reach a height of 10R, where R is the radius of the earth, may be described in terms of escape velocity v_(e ) such that v_(i)= sqrt((x)/(y)) xx v_(e ) . The value of x will be __________ .

A body is projected vertically upwards with a speed of sqrt((GM)/R) ( M is mass and R is radius of earth ) . The body will attain a height of

A body is projected vertically upwards with a speed of sqrt((GM)/R) ( M is mass and R is radius of earth ) . The body will attain a height of

A body is projected vertically from the surface of the earth of radius R with velocity equal to half of the escape velocity. The maximum height reached by the body is

Find the mass of earth (Given the radius of earth R= 6.4 xx 10^6 m) .