Which of the following is true in a triangle `ABC?` (1) `(b+c) sin((B_C)/2)=2a cos(A/2)` (2) `(b+c)cos(A/2)= 2a sin((B-C)/2)`

Show that, in a triangle ABC. a^(2) = (b - c)^(2) cos^(2) (A/2) + (b + c)^(2) sin^(2) (A/2) .

In triangle ABC,a,b,c are the lengths of its sides and A,B,C are the angles of triangle ABC .The correct relation is given by (a) (b-c)sin((B-C)/(2))=a(cos A)/(2) (b) (b-c)cos((A)/(2))=as in(B-C)/(2)(c)(b+c)sin((B+C)/(2))=a(cos A)/(2)(d)(b-c)cos((A)/(2))=2a(sin(B+C))/(2)

In any triangle ABC, (a+b)^2 sin^2 ((C )/(2))+(a-b)^2 cos^2 ((C )/(2))= .

In any triangle ABC, show that : 2a cos (B/2) cos (C/2) = (a+b+c) sin (A/2)

Choose the correct option In a triangle ABC, sin((A+B)/2) is equal to a) cos(B-C)/2 b) cos(C-A)/2 c) cos(A/2) d) cos (C/2)

If in triangle ABC, a^2+2bc-(b^2+c^2)= ab sin (C/2) cos( C/2) , then cot (B+C) =

If A, B, C are interior angle of triangle ABC then show that sin ((A+B)/2) + cos (( A+ B)/2) = cos (C/2) + sin (C/2)

In any triangle ABC,show that: 2a cos((B)/(2))cos((C)/(2))=(a+b+c)sin((A)/(2))

In any triangle ABC, prove that (i) (a-b)/( c)=("sin"(A-B)/(2))/("cos"( C)/(2)) (ii) (b-c)/(a)=("sin"(B-C)/(2))/("cos"(A)/(2))

Prove in any triangle ABC that (i) a(cos B+cos C)=2(b+c) "sin"^(2)(A)/(2) (ii) a(cos C- cosB)= 2(b-c )"cos"^(2)(A)/(2)