`I_n=intsin^n x dx`

intsin^(2) n x dx

intsin^(2) n x dx

If I_n = int sin^n x dx then nI_n - (n - 1)I_(n-2) = f(x)+c where f(x) =

intsin^(5) x dx

intsin^(5) x dx

intsin^2b\ x\ dx

If I_n = int sin^n x \ dx, then n I_n - (n-1) I_(n-2) equals

intsin^2x/2\ dx

If I_n = int tan^n x dx , then prove that I_n = (tan^(n-1) x)/(n - 1) - I_(n - 2) . Hence find int tan^7 x dx