`lim_(n->oo)cos^2(pi(3sqrt(n^3+n^2+2n)-n))` where n is an integer,equals

lim_(ntooo)cos (pisqrt(n^(2)+n)) (where n is an integer) is equal to

Evaluate the limit: (lim_(n rarr oo)cos(pi sqrt(n^(2)+n)) when n is an integer

Lim_(n->oo)(sqrt(n^2+n+1)-[n^2+n+1])(n in I) where [ ] denote the greatest integer functionis is

Find the value of lim_(n rarr oo)cos[pi sqrt(n^(2)+n)],n in Z is equal to

lim_(n->oo) ((sqrt(n^2+n)-1)/n)^(2sqrt(n^2+n)-1)

The value of lim_(nto oo)(sqrt(n^(2)+n+1)-[sqrt(n^(2)+n+1)]) where [.] denotes the greatest integer function is

The value of lim_(nto oo)(sqrt(n^(2)+n+1)-[sqrt(n^(2)+n+1)]) where [.] denotes the greatest integer function is

lim_(n rarr oo) n(sqrt(n^(2)+8)-n) =

lim_(n rarr oo) n(sqrt(n^(2)+6)-n) =