The number of real number in `{sqrt2,sqrt4,sqrt6,sqrt8...200}`, which are divisible by both `sqrt2 and sqrt8`,are

(sqrt2+sqrt3)(sqrt3+sqrt8)

(2sqrt8)/(sqrt6-sqrt2)=

FOIL (sqrt8-sqrt2)(sqrt8-sqrt2)

Arrange in descending order: 3sqrt5,6sqrt26,4sqrt8,sqrt2

From the pairs of numbers given below, pick out those whose product is a natural number or a fraction. i) sqrt3 , sqrt12 ii) sqrt3 , sqrt1.2 iii) sqrt5 , sqrt8 iv) sqrt0.5 , sqrt8

(sqrt(2)-sqrt(8))/(sqrt(2)+sqrt(8))

Find the value of (sqrt2 + sqrt8)^(2)

The number of real solutions the equation sqrt(x+14-8sqrt(x-2))+sqrt(x+23-10sqrt(x-2))=3 are

The number of real solutions the equation sqrt(x+14-8sqrt(x-2))+sqrt(x+23-10sqrt(x-2))=3 are

Which one of the following are irrational numbers ? (i) sqrt(2+sqrt3) , (ii) sqrt(4+sqrt25) , (iii) root3(5+sqrt7) , (iv) sqrt(8-root3(8))