In a shotput event, an athlete throws the shotput of mass `10kg` with an initial speed of `1ms^(-1)` at `45^(@)` from a heigth `1.5m` above ground. Assuming air resistance to be negligible and acceleration due to gravity to be `10ms^(-2)`, the kinetic energy of the shotput when it just reaches the ground will be

Options

A. 2.5j
B. 5.0j
C. 52.5j
D. 155.0j

Explanation

To solve the problem, we need to calculate the kinetic energy of the shotput when it just reaches the ground. We'll use the principle of conservation of mechanical energy, which states that the total mechanical energy (kinetic energy + potential energy) remains constant in the absence of non-conservative forces like air resistance.

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Mass of the shotput, \( m = 10 \, \text{kg} \)
- Initial speed, \( v = 1 \, \text{m/s} \)
- Angle of projection, \( \theta = 45^\circ \) (not needed for this calculation)
...