A bullet of mass `m` fired at `30^(@)` to the horizontal leaves the barrel of the gun with a velocity `upsilon`. The bullet hits a soft target at a height `h` above the ground while it is moving downward and emerges out with half the kinetic energy it had before hitting the target.
Which of the following statements are correct in respect of bullet after it emerges out of the target ?

Options

A. (a) The velocity of the bullet will be reduced to half its initial value.
(b) The velocity of the bullet will be more than half of its earlier velocity.

(c) The bullet will continue to move along the same parabolic path.
B. The bullet will move in a different parabolic path.
C. The bullet will fall vertically downward after hitting the target
D. The internal energy of the particles of the target will increase.

Explanation

To solve the problem, we need to analyze the motion of the bullet before and after it hits the soft target. We will also determine the effects of the bullet's kinetic energy loss on its motion and the target.

### Step-by-Step Solution:

1. **Understanding Initial Conditions**:
- The bullet is fired at an angle of \(30^\circ\) with an initial velocity \(v\).
- The bullet has a mass \(m\) and is moving in a parabolic trajectory until it hits the target at height \(h\).

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