Two bodies of unequal mass are moving in the same direction with equal kinetic energy. The two bodies are brought to rest by applying retarding force of same magnitude. How would the distance moved by them before coming to rest compare ?

Explanation

To solve the problem, we need to analyze the motion of two bodies with unequal masses but equal kinetic energy, which are brought to rest by applying a retarding force of the same magnitude. Let's denote the two bodies as Body 1 with mass \( m_1 \) and Body 2 with mass \( m_2 \).

### Step-by-Step Solution:

1. **Understanding Kinetic Energy**:
Both bodies have the same kinetic energy \( K \). The kinetic energy of an object is given by the formula:
\[
K = \frac{1}{2} mv^2
...