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Using the data given below: E(Cr(2)O(7...

Using the data given below:
`E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V`
`E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V`
Mark the strongest reducing agent.

A

`Cl^(-)`

B

`Cr`

C

`Cr^(3+)`

D

`Mn ^(2+)`

Text Solution

AI Generated Solution

To determine the strongest reducing agent from the given data, we will follow these steps: ### Step 1: Understand the Concept of Reducing Agents A reducing agent is a substance that donates electrons to another species and is itself oxidized in the process. The strength of a reducing agent can be determined by its oxidation potential; the higher the oxidation potential, the stronger the reducing agent. ### Step 2: Identify the Given Reduction Potentials We have the following reduction potentials: 1. \( E^\circ (Cr_2O_7^{2-} | Cr^{3+}) = 1.33 \, V \) ...
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Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V In which option the order of reducing power is correct?

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V In which option the order of reducing power is correct?

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V Find the most stable ion in its reduced forms

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V Find the most stable oxidised species.

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V Find the most stable oxidised species.

Using tha data given below is reducing potenial. E_(Cr_2O_7^(2-)//Cr^(3+))^@ =1.33 V , E_(Cl_2//Cl^-)^@ =1.36 V E_(MnO_4^(-)//Mn^(2+))^@ =1.51 V , E_(Cr^(3+) // Cr)^@ =- 0.74 V find out which of the following is the strongest oxidising agent.

Given E_(Cl_(2)//Cl^(-))^(@)=1.36V,E_(Cr^(3+)//Cr)^(@)=-0.74V E_("Cr_(2)O_(7)^(2-)//Cr^(3+))^(@)=1.33V,E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51V Among the following, the strongest reducing agent is

E_(Mn^(2+)//MnO_(4)^(-))^(0)=-1.51V E_(MnO_(2)//Mn^(+2))^(0)=+1.23V E_(MnO_(4)^(-)//MnO_(2)=? (All in acidic medium)

given E_(S_(2)O_(8)^(2-)//SO_(4)^(2-)^(@)=2.05V E_(Br_(2)//Br^(-))^(@)=1.40V E_(Au^(3+)//Au)^(@)=1.10V ,brgt E_(O_(2)//H_(2)O)^(@)=1.20V Which of the following is the strongest oxidizing agent ?

Select the correct statement if- E_(Mg^(2+)//Mg)^(@)=-2.4V, E_(Sn^(4+)//Sn^(2+))^(@)=0.1V, E_(MnO_(4)^(-),H^+//Mn^(2+))^(@)=1.5V, E_(I_(2)//I^(-))^(@)=0.5V

NCERT EXEMPLAR ENGLISH-ELECTROCHEMISTRY-All Questions
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  4. Given E("Cr(2)O(7)^(2-)//Cr^(3+))^(@)=1.33V,E(MnO(4)^(-)//Mn^(2+))^(@)...

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  6. Use the data given in Q.8 and find out the most stable ion in its redu...

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