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Using the data given below: E(Cr(2)O(7...

Using the data given below:
`E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V`
`E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V`
Find the most stable oxidised species.

A

`Cr^(3+)`

B

`MnO_(4)^(-)`

C

`Cr_(2)O_(7)^(2-)`

D

`Mn^(2+)`

Text Solution

AI Generated Solution

To determine the most stable oxidized species from the given standard reduction potentials, we need to analyze the provided data step by step. ### Step 1: Understand the Given Data We have the following standard reduction potentials: 1. \( E^\circ_{Cr_2O_7^{2-} | Cr^{3+}} = 1.33 \, V \) 2. \( E^\circ_{Cl_2 | Cl^-} = 1.36 \, V \) 3. \( E^\circ_{MnO_4^{-} | Mn^{2+}} = 1.51 \, V \) 4. \( E^\circ_{Cr^{3+} | Cr} = -0.74 \, V \) ...
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Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V Find the most stable ion in its reduced forms

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V Mark the strongest reducing agent.

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V Mark the strongest reducing agent.

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V In which option the order of reducing power is correct?

Using the data given below: E_(Cr_(2)O_(7)^(2-)|Cr^(3+))^(@)=1.33V E_(Cl_(2)|Cl^(-))^(@)=1.36V E_(MnO_(4)^(-)|Mn^(2+))^(@)=1.51V E_(Cr^(3+)|Cr)=-0.74V In which option the order of reducing power is correct?

Using tha data given below is reducing potenial. E_(Cr_2O_7^(2-)//Cr^(3+))^@ =1.33 V , E_(Cl_2//Cl^-)^@ =1.36 V E_(MnO_4^(-)//Mn^(2+))^@ =1.51 V , E_(Cr^(3+) // Cr)^@ =- 0.74 V find out which of the following is the strongest oxidising agent.

E_(Mn^(2+)//MnO_(4)^(-))^(0)=-1.51V E_(MnO_(2)//Mn^(+2))^(0)=+1.23V E_(MnO_(4)^(-)//MnO_(2)=? (All in acidic medium)

Given E_(Cl_(2)//Cl^(-))^(@)=1.36V,E_(Cr^(3+)//Cr)^(@)=-0.74V E_("Cr_(2)O_(7)^(2-)//Cr^(3+))^(@)=1.33V,E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51V Among the following, the strongest reducing agent is

Select the correct statement if- E_(Mg^(2+)//Mg)^(@)=-2.4V, E_(Sn^(4+)//Sn^(2+))^(@)=0.1V, E_(MnO_(4)^(-),H^+//Mn^(2+))^(@)=1.5V, E_(I_(2)//I^(-))^(@)=0.5V

Given E_("Cr_(2)O_(7)^(2-)//Cr^(3+))^(@)=1.33V,E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51V Among the following, the strongest reducing agent is E_(Cr^(3+)//Cr)^(@)=-0.74V^(x),E_(MnO_(4)^(-)//Mn^(2+))^(@)=1.51V E_(Cr_(2)O_(7)^(2-)//Cr^(3+))^(@)=1.33V,E_(Cl//Cl^(-))^(@)=1.36V Based on the data given above strongest oxidising agent will be

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