`E_("cell")^(@)=1.1V` for Daniel cell. Which of the following expressions are correct description of state of equilibrium in this cell?

Options

A. `1.1 =k_(c)`
B. `(2.303RT)/(2F)"log"k_(c)=1.1`
C. `"log"k_(c)=(2.2)/(0.059)`
D. ` "log" k_(c)=1.1`

Explanation

To solve the problem regarding the equilibrium state of the Daniel cell with a given standard cell potential (E°cell) of 1.1 V, we can follow these steps:

### Step 1: Understand the Components of the Daniel Cell
The Daniel cell consists of two half-cells:
- The anode where zinc (Zn) is oxidized to zinc ions (Zn²⁺).
- The cathode where copper ions (Cu²⁺) are reduced to copper metal (Cu).

### Step 2: Write the Half-Reactions
...