`Lambda_(m)^(@)H_(2)O` is equal to:

Options

A. `Lambda_(m(HCl))^(@)+Lambda_(m(NaOH))^(@)-Lambda_(m(NaCl))^(@)`
B. `Lambda_(m(HNO_(3))^(@)+Lambda_(m(NaNO_(3)))^(@))-Lambda_(m(NaOH))^(@)`
C. `Lambda_(m(HNO_(3)))^(@)+Lambda_(m(NaOH))^(@)-Lambda_(m(NaNO_(3)))^(@)`
D. `Lambda_(m(NH_(4)OH))^(@)+Lambda_(m(HCl))^(@)-Lambda_(m(NH_(4)Cl))^(@)`

Explanation

To find the limiting molar conductivity of water, denoted as \( \Lambda_m^{\circ} H_2O \), we need to analyze the given options based on the dissociation of the ions involved.

### Step-by-Step Solution:

1. **Understanding Limiting Molar Conductivity**:
- Limiting molar conductivity (\( \Lambda_m^{\circ} \)) is defined as the conductivity of an electrolyte solution at infinite dilution where the ions are completely dissociated.

2. **Identifying the Ions**:
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