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If momentum (p), area (A) and time(t) ar...

If momentum `(p)`, area `(A)` and time`(t) `are taken to be fundamental quantities then energy has the dimensional formula

A

`[pA^(-1)T^(-1)]`

B

`[P^(2)AT]`

C

`[pA^(-1//2)T]`

D

`[pA^(1//2)T^(-1)]`

Text Solution

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The correct Answer is:
To find the dimensional formula of energy (E) in terms of momentum (p), area (A), and time (t), we can follow these steps: ### Step 1: Understand the definitions of the quantities - **Momentum (p)** is defined as the product of mass (m) and velocity (v). Therefore, the dimensional formula of momentum is: \[ [p] = [m][v] = [m][L][T^{-1}] = mL T^{-1} \] - **Area (A)** is defined as length squared. Therefore, the dimensional formula of area is: \[ [A] = [L^2] \] - **Time (t)** has the dimensional formula: \[ [t] = [T] \] ### Step 2: Write the relationship for energy Energy can be expressed in terms of momentum, area, and time as: \[ E \propto p^A A^B t^C \] where A, B, and C are the powers to which momentum, area, and time are raised, respectively. ### Step 3: Substitute the dimensional formulas Substituting the dimensional formulas into the equation gives: \[ [E] \propto (mL T^{-1})^A (L^2)^B (T)^C \] ### Step 4: Expand the equation Expanding this, we get: \[ [E] \propto m^A L^{A + 2B} T^{-A + C} \] ### Step 5: Set the dimensional formula of energy The dimensional formula of energy (E) is known to be: \[ [E] = mL^2 T^{-2} \] ### Step 6: Equate the powers of dimensions Now, we can equate the powers of each dimension from both sides: 1. For mass (m): \[ A = 1 \] 2. For length (L): \[ A + 2B = 2 \] 3. For time (T): \[ -A + C = -2 \] ### Step 7: Solve the equations From the first equation, we have: \[ A = 1 \] Substituting \(A = 1\) into the second equation: \[ 1 + 2B = 2 \implies 2B = 1 \implies B = \frac{1}{2} \] Substituting \(A = 1\) into the third equation: \[ -1 + C = -2 \implies C = -1 \] ### Step 8: Write the final expression for energy Now substituting the values of A, B, and C back into the expression for energy: \[ E \propto p^1 A^{\frac{1}{2}} t^{-1} \] Thus, the dimensional formula of energy in terms of momentum, area, and time is: \[ E \propto p^1 A^{\frac{1}{2}} t^{-1} \]

To find the dimensional formula of energy (E) in terms of momentum (p), area (A), and time (t), we can follow these steps: ### Step 1: Understand the definitions of the quantities - **Momentum (p)** is defined as the product of mass (m) and velocity (v). Therefore, the dimensional formula of momentum is: \[ [p] = [m][v] = [m][L][T^{-1}] = mL T^{-1} \] ...
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