Home
Class 11
PHYSICS
The vernier scale of a travelling micros...

The vernier scale of a travelling microscope has `50` divisions which coincide with `49` main scale divisions. If each main scale division is `0.5 mm`, the minimum inaccuracy in the measurement of distance is

Text Solution

AI Generated Solution

To solve the problem step by step, we need to find the minimum inaccuracy in the measurement of distance using the given information about the vernier scale of a travelling microscope. ### Step 1: Understand the problem We know that the vernier scale has 50 divisions that coincide with 49 main scale divisions. Each main scale division (MSD) is given as 0.5 mm. Our goal is to find the least count of the vernier scale, which represents the minimum inaccuracy in the measurement. ### Step 2: Calculate the value of one Vernier scale division (VSD) Since 50 vernier scale divisions coincide with 49 main scale divisions, we can express this relationship mathematically: ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • UNITS AND MEASUREMENTS

    NCERT EXEMPLAR ENGLISH|Exercise Long Answer Type Questions|9 Videos
  • UNITS AND MEASUREMENTS

    NCERT EXEMPLAR ENGLISH|Exercise Very Short Answer Type Questions|6 Videos
  • THERMODYNAMICS

    NCERT EXEMPLAR ENGLISH|Exercise LONG ANSWER TYPE QUESTIONS|5 Videos
  • WAVES

    NCERT EXEMPLAR ENGLISH|Exercise LONG ANSWER TYPE QUESTIONS|5 Videos

Similar Questions

Explore conceptually related problems

In a given slide callipers 10 division of its vernier coincides with its 9 main scale divisions. If one main scale division is equal to 0.5 mm then find its least count.

The vernier of a circular scale is divided into 30 divisons, which coincides with 29 main scale divisions. If each main scale division is (1//2)^@ the least count of the instrument is (1^@=60')

Knowledge Check

  • The vernier scale of a travelling microscope has 50 divisions which coincide with 49 main scale divisions. If each main scale division is 0.5 mm, then the least count of the microscope is

    A
    0.01 cm
    B
    0.5 mm
    C
    0.01 mm
    D
    0.5 cm
  • Similar Questions

    Explore conceptually related problems

    The vernier constant of a vernier calipers is 0.001 cm . If 49 main scale divisions coincide with 50 vernier scale divisions, then the value of 1 main scale divisions is .

    If 25venier scale divisions coincide with 20 main scale divisions. Find least count of venier calliper. ( One main scale division = 1mm )

    If 25venier scale divisions coincide with 20 main scale divisions. Find least count of venier calliper. ( One main scale division = 1mm )

    The vernier constant of a vernier callipers is 0.001 cm . If 49 main scale divisions coincide with 50 vernier scale devisions, then the value of 1 main scale divisions is .

    A vernier callipers has 20 divisions on the vernier scale which coincide with 19 divisions on the main scale. The least count of the instrument is 0.1 mm. The main scale divisions are of

    The smallest division on main scale of a vernier caliper is 1 mm and 10 vernier divisions coincide with 9 main scale divisions. While measuring the length of a line, the zero mark of the vernier scale lies between 10.2 cm and 10.3 cm and the third division of vernier scale coincides with a main scale division. (a) Determine the least count of the caliper. (b) Find the length of the line.

    The main scale of vernier callipers has 10 equal divisions in 1 cm and 10 vernier scale divisions coincide with 9 main scale divisions, when both the jaws are in contact. Now, the above instrument is used to measure the external diameter of a cylinder. The 43rd division on the main scale is observed to the left of the zero of the vernier, when the object is held tightly in between the two jaws and the seventh division of the vernier coinsides with a division on the main scale, then