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A transverse harmonic wave on a string i...

A transverse harmonic wave on a string is described by `y(x,t)=3.0sin(36t+0.018x+pi//4)` where x, y are in cm, t in second. The positive direction of x is from left to right . (i) Is this a travelling or stationary wave ? If travellying, what are the speed and direction of its propagation ? (ii) what are its amplitude and frequency ? (iii) what is the inital phase at the origing ? (iv) What is the least distance between two successive creests in the wave?

A

the wave is travelling from right to left

B

the speed of the wave is 20 m/s

C

frequecny of the wave is 5.7 Hz

D

the least distance between two successive crests in the wave is 2.5 cm

Text Solution

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To solve the problem step by step, we will analyze the given wave equation and extract the required information. **Given Wave Equation:** \[ y(x,t) = 3.0 \sin(36t + 0.018x + \frac{\pi}{4}) \] where \( x \) and \( y \) are in cm, and \( t \) is in seconds. ### Step 1: Determine if the wave is traveling or stationary The general form of a traveling wave is: \[ y(x,t) = A \sin(\omega t + kx + \phi) \] Here, the term \( \omega t + kx \) indicates the wave's propagation direction. If it is of the form \( \omega t - kx \), the wave travels in the positive x-direction; if it is \( \omega t + kx \), it travels in the negative x-direction. **Analysis:** - In our equation, we have \( 36t + 0.018x \), which indicates that the wave is traveling in the negative x-direction. ### Step 2: Calculate the speed of the wave The speed \( v \) of a wave can be calculated using the relationship: \[ v = \frac{\omega}{k} \] Where: - \( \omega = 36 \, \text{rad/s} \) - \( k = 0.018 \, \text{cm}^{-1} \) **Calculation:** 1. Convert \( k \) to SI units: \[ k = 0.018 \, \text{cm}^{-1} = 0.018 \times 100 \, \text{m}^{-1} = 1.8 \, \text{m}^{-1} \] 2. Calculate the speed: \[ v = \frac{\omega}{k} = \frac{36 \, \text{rad/s}}{1.8 \, \text{m}^{-1}} = 20 \, \text{m/s} \] ### Step 3: Determine the amplitude and frequency - The amplitude \( A \) is the coefficient in front of the sine function, which is \( 3.0 \, \text{cm} \). - The frequency \( f \) can be calculated using: \[ \omega = 2\pi f \] Thus, \[ f = \frac{\omega}{2\pi} = \frac{36}{2\pi} \approx \frac{36}{6.28} \approx 5.73 \, \text{Hz} \] ### Step 4: Find the initial phase at the origin The initial phase at the origin (when \( x = 0 \) and \( t = 0 \)) can be found by substituting these values into the wave equation: \[ y(0,0) = 3.0 \sin(0 + 0 + \frac{\pi}{4}) = 3.0 \sin(\frac{\pi}{4}) = 3.0 \cdot \frac{\sqrt{2}}{2} = \frac{3\sqrt{2}}{2} \, \text{cm} \] The initial phase is \( \frac{\pi}{4} \). ### Step 5: Calculate the least distance between two successive crests (wavelength) The wavelength \( \lambda \) can be found using: \[ k = \frac{2\pi}{\lambda} \] Thus, \[ \lambda = \frac{2\pi}{k} = \frac{2\pi}{0.018} \approx \frac{6.28}{0.018} \approx 348.89 \, \text{cm} \] ### Summary of Results: 1. The wave is traveling in the negative x-direction. 2. Speed of the wave: \( 20 \, \text{m/s} \). 3. Amplitude: \( 3.0 \, \text{cm} \). 4. Frequency: \( 5.7 \, \text{Hz} \). 5. Initial phase at the origin: \( \frac{\pi}{4} \). 6. Wavelength (least distance between two successive crests): \( 348.89 \, \text{cm} \).

To solve the problem step by step, we will analyze the given wave equation and extract the required information. **Given Wave Equation:** \[ y(x,t) = 3.0 \sin(36t + 0.018x + \frac{\pi}{4}) \] where \( x \) and \( y \) are in cm, and \( t \) is in seconds. ### Step 1: Determine if the wave is traveling or stationary The general form of a traveling wave is: ...
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Knowledge Check

  • A transverse harmonic wave on a string is described by y(x, t) = 3sin ( 36t + 0.018x + π/4) where x and Y are in cm and t is in s. Which of the following statements is incorrect?

    A
    The waves is travelling in negative x-direction
    B
    The amplitude of the wave is 3 cm
    C
    The speed of the wave is `20ms^(-1)`
    D
    The frequency of the wave is`9/pi`Hz.
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