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The transverse displacement of a string ...

The transverse displacement of a string (clamped at its both ends ) is given by `y(x,t)=0.06sin(2pix//3)cos(120pit).`
All the points on the string between two consecutive nodes vibrate with

A

same frequency

B

same phase

C

same energy

D

different amplitude

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the given equation of the transverse displacement of a string, which is: \[ y(x,t) = 0.06 \sin\left(\frac{2\pi x}{3}\right) \cos(120\pi t) \] This equation represents a standing wave on a string that is clamped at both ends. ### Step 1: Identify the form of the wave equation The equation can be compared to the general form of a standing wave: \[ y(x,t) = A \sin(kx) \cos(\omega t) \] Here, \( A = 0.06 \), \( k = \frac{2\pi}{3} \), and \( \omega = 120\pi \). ### Step 2: Determine the wave properties 1. **Wavelength (\( \lambda \))**: The wave number \( k \) is related to the wavelength by the formula \( k = \frac{2\pi}{\lambda} \). Therefore, we can find \( \lambda \): \[ k = \frac{2\pi}{3} \implies \lambda = 3 \] 2. **Frequency (\( f \))**: The angular frequency \( \omega \) is related to the frequency by \( \omega = 2\pi f \). Thus, we can find \( f \): \[ \omega = 120\pi \implies f = 60 \text{ Hz} \] ### Step 3: Analyze the points between two consecutive nodes In a standing wave, nodes are points where the displacement is always zero. The distance between two consecutive nodes is half the wavelength: \[ \text{Distance between nodes} = \frac{\lambda}{2} = \frac{3}{2} = 1.5 \] The points between two consecutive nodes will vibrate with the same frequency, but they will have different amplitudes due to the nature of standing waves. ### Step 4: Conclusion on the vibration characteristics - **Same Frequency**: All points between two consecutive nodes vibrate with the same frequency \( f = 60 \text{ Hz} \). - **Different Amplitudes**: The amplitude varies with position \( x \) as given by the sine function, which means the amplitude is not constant. - **Same Phase**: All points between two nodes are in phase at any given instant of time due to the nature of the cosine function. ### Final Answer All the points on the string between two consecutive nodes vibrate with the **same frequency** and **same phase**, but they have **different amplitudes**.

To solve the problem, we need to analyze the given equation of the transverse displacement of a string, which is: \[ y(x,t) = 0.06 \sin\left(\frac{2\pi x}{3}\right) \cos(120\pi t) \] This equation represents a standing wave on a string that is clamped at both ends. ### Step 1: Identify the form of the wave equation The equation can be compared to the general form of a standing wave: ...
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