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A train, standing in a station yard, blo...

A train, standing in a station yard, blows a whistle of frequency 400Hz in still air. The wind starts blowing in the direction from the yard to the station with a speed of 10m//s. Given that the speed sound in still air is `34om//s,

A

the frequency of sound as heard by an observer standing on the platform is 400 Hz

B

the speed of sound for the observed standing on the platform is 350 m/s

C

the frequency of sound as heard by the oberver standing on the platform will increases

D

the fequency of sound as heard by the observer standing on the platform will decreases

Text Solution

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The correct Answer is:
To solve the problem step by step, we will analyze the situation involving the train whistle, the observer, and the effect of the wind on the sound frequency. ### Step 1: Identify the given information - Frequency of the whistle (f) = 400 Hz - Speed of sound in still air (V) = 340 m/s - Speed of wind (V_wind) = 10 m/s (blowing from the yard to the station) ### Step 2: Determine the effective speed of sound Since the wind is blowing in the same direction as the sound, the effective speed of sound (V_effective) for the observer will be the speed of sound in still air plus the speed of the wind: \[ V_{\text{effective}} = V + V_{\text{wind}} \] \[ V_{\text{effective}} = 340 \, \text{m/s} + 10 \, \text{m/s} = 350 \, \text{m/s} \] ### Step 3: Analyze the frequency heard by the observer The frequency of sound heard by the observer (f_apparent) can be calculated using the formula for the Doppler effect when both the source and observer are stationary: \[ f_{\text{apparent}} = f \cdot \frac{V_{\text{effective}}}{V} \] Since the observer is stationary and the source is also stationary, we can simplify this to: \[ f_{\text{apparent}} = f \] Thus, the frequency of sound as heard by the observer remains: \[ f_{\text{apparent}} = 400 \, \text{Hz} \] ### Step 4: Conclusion on frequency and speed of sound - The frequency of sound as heard by the observer is **400 Hz** (no change). - The effective speed of sound for the observer is **350 m/s**. ### Step 5: Evaluate the options - **Option A**: The frequency of sound as heard by an observer standing on the platform is 400 Hz. **(Correct)** - **Option B**: The speed of sound for the observer standing on the platform is 350 m/s. **(Correct)** - **Option C**: The frequency of sound as heard by the observer standing on the platform will increase. **(Incorrect)** - **Option D**: The frequency of sound as heard by the observer standing on the platform will decrease. **(Incorrect)** ### Final Answer - The correct options are A and B. ---

To solve the problem step by step, we will analyze the situation involving the train whistle, the observer, and the effect of the wind on the sound frequency. ### Step 1: Identify the given information - Frequency of the whistle (f) = 400 Hz - Speed of sound in still air (V) = 340 m/s - Speed of wind (V_wind) = 10 m/s (blowing from the yard to the station) ### Step 2: Determine the effective speed of sound ...
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