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For the harmonic travelling wave y=2cos2...

For the harmonic travelling wave y=2cos2pi(10t-0.0080x+3.5)` where x and y ar in cm and t is in second. What is the phase diffference between the oscillatory motion at two points separated by a distance of

A

4m

B

`0.5 m`

C

`(lambda)/(2)`

D

`(3lambda)/(4)` (at a given instant of time)

Text Solution

AI Generated Solution

To find the phase difference between the oscillatory motion at two points separated by a given distance for the harmonic traveling wave described by the equation \( y = 2 \cos(2\pi(10t - 0.0080x) + 3.5) \), we will follow these steps: ### Step 1: Identify the wave parameters The wave equation is given as: \[ y = 2 \cos(2\pi(10t - 0.0080x) + 3.5) \] From this equation, we can identify the following parameters: - Angular frequency \( \omega = 2\pi \times 10 = 20\pi \) rad/s ...
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