which of the following is a network solid? a) Sulphur dioxide (Solid) b) Iodine c) Diamond d) Ice

Options

A. `SO_(2)("solid")`
B. `I_(2)`
C. Diamond
D. `H_(2)O` (ice)

Explanation

To determine which of the following is a network solid among the given options, we will analyze each substance based on its structure and bonding characteristics.

### Step-by-Step Solution:

1. **Analyze Sulphur Dioxide (SO₂)**:
- Sulphur dioxide has a bent molecular structure where one sulfur atom is bonded to two oxygen atoms through double bonds.
- The structure is discrete and does not form an extended network of atoms.
- **Conclusion**: Sulphur dioxide is not a network solid.

2. **Analyze Iodine (I₂)**:
- Iodine exists as diatomic molecules (I₂) where two iodine atoms are bonded together by a single bond.
- This structure is also discrete and does not extend into a network.
- **Conclusion**: Iodine is not a network solid.

3. **Analyze Diamond**:
- Diamond has a three-dimensional (3D) network structure where each carbon atom is covalently bonded to four other carbon atoms in a tetrahedral arrangement.
- This extensive bonding creates a rigid and continuous network throughout the entire structure.
- **Conclusion**: Diamond is a network solid.

4. **Analyze Ice (H₂O)**:
- Ice has a hexagonal crystalline structure where water molecules are held together by hydrogen bonds.
- Although there are interactions between molecules, the structure does not form a continuous network of covalent bonds like in diamond.
- **Conclusion**: Ice is not a network solid.

### Final Answer:
Based on the analysis, the only network solid among the given options is **c) Diamond**.

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