When 0.1 mol `CoCl_(3)(NH_(3))_(5)` is treated with excess of `AgNO_(3)`, 0.2 mole of AgCl are obtained. The conductivity of solution will correspond to

Options

A. 1 : 3 electrolyte
B. 1 : 2 electrolyte
C. 1 : 1 electrolyte
D. 3 : 1 electrolyte

Explanation

To solve the question, we need to analyze the reaction of the coordination compound \( CoCl_3(NH_3)_5 \) with excess \( AgNO_3 \) and determine the conductivity of the resulting solution.

### Step-by-Step Solution:

1. **Identify the Coordination Compound:**
The coordination compound given is \( CoCl_3(NH_3)_5 \). This indicates that it has 3 chloride ions coordinated to the cobalt ion and 5 ammonia molecules.

2. **Reaction with Silver Nitrate:**
When \( CoCl_3(NH_3)_5 \) is treated with excess \( AgNO_3 \), the chloride ions (\( Cl^- \)) will react with \( Ag^+ \) ions to form silver chloride (\( AgCl \)). The reaction can be represented as:
\[ Ag^+ + Cl^- \rightarrow AgCl \]

3. **Calculate the Moles of Chloride Ions:**
According to the problem, 0.2 moles of \( AgCl \) are formed. Since 1 mole of \( AgCl \) is produced from 1 mole of \( Cl^- \), the number of moles of \( Cl^- \) ions that reacted is:
\[ \text{Moles of } Cl^- = 0.2 \text{ moles} \]

4. **Determine the Number of Chloride Ions in the Complex:**
The initial coordination compound \( CoCl_3(NH_3)_5 \) contains 3 chloride ions. However, since we obtained 0.2 moles of \( AgCl \), it indicates that 2 of the chloride ions must be released into the solution. Therefore, there are 2 chloride ions that are ionizable from the complex.

5. **Identify the Remaining Components:**
After the reaction, the remaining part of the complex will be:
\[ Co(NH_3)_5Cl^2+ \]
This indicates that there is 1 cationic part \( Co(NH_3)_5Cl^{2+} \) and 2 anions \( Cl^- \).

6. **Determine the Total Number of Ions in Solution:**
When the complex dissociates, it produces:
- 1 cation: \( Co(NH_3)_5Cl^{2+} \)
- 2 anions: \( 2Cl^- \)

Therefore, the total number of ions produced in the solution is:
\[ 1 + 2 = 3 \text{ ions} \]

7. **Conductivity Correspondence:**
The conductivity of a solution is directly related to the number of ions present. Since we have 3 ions, the conductivity will correspond to an electrolyte that dissociates into 3 ions.

### Final Answer:
The conductivity of the solution will correspond to an electrolyte that dissociates into **3 ions**.