Due to the presence of ambidenate ligands coordination compounds show isomerism. Palladium complexes of the type `[Pd(C_(6)H_(5))_(2)(SCN)_(2)]` & `[Pd(C_(6)H_(5))_(2)(NCS)_(2)]` are

Options

A. linkage isomers
B. Coordination isomers
C. ionisation isomers
D. geometrical isomers

Explanation

To solve the question regarding the palladium complexes `[Pd(C₆H₅)₂(SCN)₂]` and `[Pd(C₆H₅)₂(NCS)₂]`, we need to analyze the nature of the ligands involved and how they contribute to isomerism.

### Step-by-Step Solution:

1. **Identify the Ligands**:
- The ligands in the given complexes are thiocyanate (SCN⁻) and isothiocyanate (NCS⁻). Both of these ligands are ambidentate, meaning they can coordinate to the metal through different atoms (sulfur in SCN and nitrogen in NCS).

2. **Understanding Ambidentate Ligands**:
- Ambidentate ligands have two different atoms that can bond to the central metal atom. In this case, SCN can bind through sulfur (S) or nitrogen (N), and NCS can bind through nitrogen (N) or sulfur (S).

3. **Determine the Isomerism**:
- The presence of ambidentate ligands leads to the possibility of linkage isomerism. Linkage isomerism occurs when a ligand can attach to the metal in more than one way, resulting in different structural isomers.

4. **Analyze the Given Complexes**:
- For the complex `[Pd(C₆H₅)₂(SCN)₂]`, the SCN⁻ ligands can bind through sulfur (forming one isomer) or through nitrogen (forming another isomer).
- For the complex `[Pd(C₆H₅)₂(NCS)₂]`, the NCS⁻ ligands can also bind through nitrogen (forming one isomer) or through sulfur (forming another isomer).

5. **Conclusion**:
- Since both complexes contain ambidentate ligands that can bind in different ways, they exhibit linkage isomerism. Therefore, the answer to the question is that these palladium complexes are linkage isomers.

### Final Answer:
The palladium complexes `[Pd(C₆H₅)₂(SCN)₂]` and `[Pd(C₆H₅)₂(NCS)₂]` are linkage isomers.