The two compounds `[Co(SO_(4))(NH_(3))_(5)]Br` and `[Co(SO_(4))(NH_(3))_(5)]Cl` represent:

Options

A. linkage isomerism
B. ionisation isomerism
C. Coordination isomerism
D. no isomerism

Explanation

To analyze the compounds `[Co(SO₄)(NH₃)₅]Br` and `[Co(SO₄)(NH₃)₅]Cl`, we can follow these steps:

### Step 1: Identify the Components of the Compounds
- The compounds consist of a cobalt (Co) ion as the central metal atom, a sulfate ion (SO₄²⁻), and five ammonia (NH₃) ligands.
- The only difference between the two compounds is the presence of bromine (Br) in one and chlorine (Cl) in the other.

### Step 2: Determine the Coordination Number
- The coordination number of cobalt in both compounds is 6, as it is surrounded by five ammonia ligands and one sulfate ion.

### Step 3: Analyze the Isomerism
- Isomerism occurs when two compounds have the same molecular formula but differ in the arrangement of atoms or groups.
- In this case, both compounds have the same ligands (5 NH₃ and 1 SO₄) but differ only in the anion (Br⁻ vs Cl⁻).
- Since the overall structure remains the same and only the anion changes, these compounds do not exhibit structural isomerism.

### Step 4: Conclusion
- The two compounds are examples of coordination compounds that differ only by their anionic components (Br and Cl). They do not represent isomers because they share the same coordination structure and only differ in the anion.

### Final Answer
The two compounds `[Co(SO₄)(NH₃)₅]Br` and `[Co(SO₄)(NH₃)₅]Cl` represent coordination compounds that differ only by their anionic components, and thus they do not exhibit isomerism.

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