Home
Class 12
CHEMISTRY
Assertion (A) Complexes of MX(6) and MX(...

Assertion (A) Complexes of `MX_(6)` and `MX_(5)L` type (X and L are unidentate) do not show geometrical isomerism.
Reason (R) Geometrical isomerism is not shown by complexes of coordination number 6.

A

Assertion and reason both are true, reason is correct explanation of assertion.

B

Assertion and reason both are true but reason is not the correct explanation of assertion.

C

Assertion is true, reason is false.

D

Assertion is false, reason is true.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the assertion and reason provided, we will analyze each statement step by step. ### Step 1: Analyze the Assertion The assertion states that complexes of the type `MX6` and `MX5L` (where X and L are unidentate ligands) do not show geometrical isomerism. - **For `MX6`:** In this complex, all six ligands are identical (X). Since there are no different ligands to create distinct arrangements, it cannot exhibit geometrical isomerism (cis/trans forms). Thus, the assertion is **true**. - **For `MX5L`:** In this complex, there are five identical ligands (X) and one different ligand (L). Since there is only one L and all other ligands are the same, it cannot form distinct geometrical isomers (cis/trans) either. Therefore, the assertion is **true** for this case as well. ### Conclusion for Step 1: The assertion is **true**. ### Step 2: Analyze the Reason The reason states that geometrical isomerism is not shown by complexes of coordination number 6. - This statement is **false**. Complexes with a coordination number of 6 can indeed show geometrical isomerism. For example, in a complex of the type `ML2X4`, where L is a bidentate ligand, geometrical isomers (cis and trans) can exist. Therefore, the reason is **false**. ### Conclusion for Step 2: The reason is **false**. ### Final Conclusion: - The assertion is true, and the reason is false. Therefore, the correct answer is option 3: "Assertion is true, and reason is false."

To solve the question regarding the assertion and reason provided, we will analyze each statement step by step. ### Step 1: Analyze the Assertion The assertion states that complexes of the type `MX6` and `MX5L` (where X and L are unidentate ligands) do not show geometrical isomerism. - **For `MX6`:** In this complex, all six ligands are identical (X). Since there are no different ligands to create distinct arrangements, it cannot exhibit geometrical isomerism (cis/trans forms). Thus, the assertion is **true**. - **For `MX5L`:** In this complex, there are five identical ligands (X) and one different ligand (L). Since there is only one L and all other ligands are the same, it cannot form distinct geometrical isomers (cis/trans) either. Therefore, the assertion is **true** for this case as well. ...
Promotional Banner

Topper's Solved these Questions

  • COORDINATION COMPOUNDS

    NCERT EXEMPLAR ENGLISH|Exercise Long Answer Type Question|5 Videos
  • COORDINATION COMPOUNDS

    NCERT EXEMPLAR ENGLISH|Exercise Maching The Columns|5 Videos
  • CHEMISTRY IN EVERYDAY LIFE

    NCERT EXEMPLAR ENGLISH|Exercise Long Answer Type Qns|4 Videos
  • D AND F-BLOCK ELEMENTS

    NCERT EXEMPLAR ENGLISH|Exercise Short Answer Type Question|20 Videos

Similar Questions

Explore conceptually related problems

Tetrahedral complex cannot show geometrical isomerism .

Which complexes show geometrical isomerism ?

Indicate the complex ion which shows geometrical isomerism.

Indicate the complex ion which shows geometrical isomerism.

Select the complex ion which shows geometrical isomerism.

Assertion:- Square planar complex do not show geometrical isomerism. Reason:- all peripheral atoms are not present in same plane.

Which of the following octahedral complexes do not show geometrical isomerism ?

Assertion : Geometrical isomerism is also called cis-trans isomerism . Reason : Tetrahedral complexes show geometrical isomerism .

Which of the following compounds/complex ions would not show geometrical isomerism ?