A fighter plane is flying horizontally at an altitude of 1.5 km with speed `720 kmh^(-1)`. At what angle of sight (w.r.t horizontal) when the target is seen, should the pilot drop the bomb in order to attack the target? `(Take g=10ms^(-2))`

Explanation

To solve the problem of determining the angle of sight at which the pilot should drop the bomb, we can follow these steps:

### Step 1: Convert the speed of the plane from km/h to m/s
The speed of the plane is given as 720 km/h. To convert this to meters per second, we use the conversion factor:
\[ \text{Speed in m/s} = \text{Speed in km/h} \times \frac{5}{18} \]
Calculating this gives:
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