If ` | vec A | =2 and | vec B| =4`, then match the relations in column I with the angle` theta` between ` vec A and vec B` in column II.
Column I, Column II
(a) ` |vec A xx vec B| =0` , (i) ` theta =30^@`
(b) `| vec A xx vec B|=0` , (ii) ` theta =45^@`
(c ) ` vec A xx vec B| =4` , (iii) ` theta =90^@`
(d) ` | vec A xxx vec B| = 4 sqrt 2` , (iv) ` theta =0^@`.

Explanation

To solve the problem, we need to analyze the cross product of two vectors \( \vec{A} \) and \( \vec{B} \) given their magnitudes and find the corresponding angles between them based on the conditions provided in Column I.

### Step-by-Step Solution:

1. **Understanding the Cross Product**:
The magnitude of the cross product of two vectors \( \vec{A} \) and \( \vec{B} \) is given by the formula:
\[
|\vec{A} \times \vec{B}| = |\vec{A}| |\vec{B}| \sin \theta
...