A hill is ` 500 m` high. Supplies are to be across the hill using a canon that can hurl packets at a speed of `125 m//s` over the hill . The canon is located at a distance of ` 800 m` from the foot to hill and can be veoved on the ground at a speed of 2 m//s , so that its distance from the hill can be adjusted. What is the shortest time inwhich a pachet can reach on the ground across the hill ? Taje ` g= 10 m//s^2`.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Determine the vertical component of the initial velocity (Uy)
We know that the height of the hill (h) is 500 m. Using the kinematic equation for vertical motion:

\[ v^2 = u^2 + 2as \]
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