Home
Class 11
CHEMISTRY
Assertion (A) . Pent-1-ene and pent-2-en...

Assertion (A) . Pent-1-ene and pent-2-ene are position isomers.
Reason (R). Position isomers differ in the position of functional group or a substituent.

A

Both A and R are correct and R is the correct explanation of A

B

Both A and R are correct but R is not the correct explanation of As

C

both A and R are not correct

D

A is not correct but R is correct

Text Solution

AI Generated Solution

The correct Answer is:
To solve the assertion and reason question regarding pent-1-ene and pent-2-ene being position isomers, we will follow these steps: ### Step 1: Define Position Isomers Position isomers are compounds that have the same molecular formula but differ in the position of a functional group or substituent in their structure. ### Step 2: Identify the Compounds The compounds in question are pent-1-ene and pent-2-ene. Both of these compounds have the same molecular formula, which is C5H10. ### Step 3: Draw the Structures - **Pent-1-ene**: The double bond is located at the first carbon. Its structure can be represented as: ``` CH2=CH-CH2-CH2-CH3 ``` - **Pent-2-ene**: The double bond is located at the second carbon. Its structure can be represented as: ``` CH3-CH=CH-CH2-CH3 ``` ### Step 4: Analyze the Structures From the structures drawn, we can see that: - Pent-1-ene has the double bond between the first and second carbon. - Pent-2-ene has the double bond between the second and third carbon. ### Step 5: Conclusion on Assertion and Reason Since both compounds have the same molecular formula (C5H10) but differ in the position of the double bond (which acts as a functional group), they are indeed position isomers. - **Assertion (A)**: Pent-1-ene and pent-2-ene are position isomers. (True) - **Reason (R)**: Position isomers differ in the position of functional group or a substituent. (True) ### Final Answer Both the assertion and the reason are correct, and the reason correctly explains the assertion. Therefore, the correct option is that both assertion and reason are correct, and the reason is the correct explanation of the assertion. ---

To solve the assertion and reason question regarding pent-1-ene and pent-2-ene being position isomers, we will follow these steps: ### Step 1: Define Position Isomers Position isomers are compounds that have the same molecular formula but differ in the position of a functional group or substituent in their structure. ### Step 2: Identify the Compounds The compounds in question are pent-1-ene and pent-2-ene. Both of these compounds have the same molecular formula, which is C5H10. ...
Promotional Banner

Topper's Solved these Questions

  • ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES

    NCERT EXEMPLAR ENGLISH|Exercise Long Answer type question|6 Videos
  • ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES

    NCERT EXEMPLAR ENGLISH|Exercise Matching the columns|5 Videos
  • HYDROGEN

    NCERT EXEMPLAR ENGLISH|Exercise LONG ANSWER TYPE QUESTIONS|8 Videos
  • REDOX REACTIONS

    NCERT EXEMPLAR ENGLISH|Exercise LONG ANSWER TYPE QUESTIONS|6 Videos

Similar Questions

Explore conceptually related problems

Conversion of Pent-1-ene to Pent-2-yne

Which are not position isomers?

Assertion : But-1-ene and 2-methylprop-1-ene are position isomers. Reason : Position isomers have same molecular formula but different arrangement of carbon atoms.

Which the sum of position of functional group and substituent in the given structure

Which is not position isomer of A?

How many positional isomers are possible for this compound

How many position isomers are possible for dichorocyclohexane?

Assertion: Nitroalkanes and alkyl nitrites exhibit funcctional isomerism. Reason: Compounds having same molecular formula but different functonal groups are called functional isomers.

Assertion (A): Metamers can also be position or chain isomers. Reason (R ): Tautomerism was introduced by C.P . Laar to explain the chemical reactivity of a substance according to two possible structrues.

Assertion (A): F_(2) undergoes disproportionation reaction. Reason (R ): Fluorine shows both positive and negative oxidation states.