Give the change in bond order in the following ionisation process?
i. `O_(2) rarr O_(2)^(o+)+e^(-)` , ii.`N_(2) rarr N_(2)^(o+)+e^(-)`

Explanation

To determine the change in bond order for the ionization processes of \( O_2 \) and \( N_2 \), we will follow these steps:

### Step 1: Understand Bond Order Calculation
Bond order is calculated using the formula:
\[ \text{Bond Order} = \frac{n_B - n_A}{2} \]
where \( n_B \) is the number of electrons in bonding orbitals and \( n_A \) is the number of electrons in anti-bonding orbitals.
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