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Roots obtain oxgyen from air soil for re...

Roots obtain oxgyen from air soil for respiration , In the absence or deficiency of `O_(2)` , root growth is restricted or completely stopped. How do the plants growing in marsh lands or swamps obtain their `O_(2)` required for root respiration ?

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To answer the question about how plants growing in marshlands or swamps obtain the oxygen required for root respiration, we can break down the solution into several steps: ### Step-by-Step Solution: 1. **Understanding Root Respiration**: - Roots of plants require oxygen (O₂) for respiration, which is essential for their growth and development. In normal conditions, roots obtain oxygen from the air in the soil. **Hint**: Remember that roots need oxygen for cellular respiration, which is crucial for energy production. ...
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Roots obtain oxygen from air in the soil for respiration. In the absence or deficiency of oxygen (O_2) , root growth is restricted or completely stopped. How do the plants growing in swamps obtain their oxygen required for root respiration?

Plants do not require O_(2) for respiration and they never give out CO_(2) .

For his 18th birthday in February Peter plants to turn a hut in the garden of his parents into a swimming pool with an artifical beach. In order to estimate the consts for heating the water and the house , peter obtains the data for the natural gas combustion and its price. What is the total energy (in MJ) needed for Peter's "winter swimming pool" calculated in 1.3 and 1.4? How much natural gas will he need, if the gas heater has an efficiency of 90.0% ? What are the different costs for the use of either natural gas or electricity ? Use the values given by PUC for your calculations and assume 100% efficiency for the electric heater. Table 1: Composition of natural gas {:("Chemical substance","mol fraction x",D_(1)H^(@)(KJ mol^(-1))^(-1),S^(@)(J mol^(-1)K^(-1))^(-1),C_(p)^(@)(J mol^(-1)K^(-1))^(-1)),(CO_(2(g)),0.0024,-393.5,213.6,37.1),(N_(2(g)) ,0.0134,0.0,191.6,29.1),(CH_(2(g)),0.9732,-74.6,186.3,35.7),(C_(2)H_(3 (g)),0.0110,-84.0,229.2,52.2),(H_(2)O_(g),-,-285.8,70.0,75.3),(H_(2)O_(g),-,-241.8,188.8,33.6),(H_(2)O_(g),-,0.0,205.2,29.4):} Equation J=E(A.Deltat)^(-1) =!! lambda "wall" . DeltaT. d^(-1) , where J= energy flow E along a temperature gradient (wall direction Z) par area A and time Deltat , d-wall thickness , lambda wall -heat conductivity , DeltaT - difference in temperature between the inside and the outside of the house.