A bar magnet of magnetic moment M and moment of inertia I (about centre, perpendicular to length) is cut into two equal pieces, perpendicular to length. Let T be the period of oscillation of the original magnet about an axis through the mid point, perpendicular to length, in a magnetic field `vecB`. What would be the similar period `T^'` for each piece?

Explanation

To solve the problem, we need to analyze the situation step by step.

### Step 1: Understand the original bar magnet's properties
The original bar magnet has a magnetic moment \( M \) and a moment of inertia \( I \) about an axis through its center, perpendicular to its length. The formula for the moment of inertia of a bar magnet of mass \( m \) and length \( l \) is given by:

\[ I = \frac{ml^2}{12} \]
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