The ratio of contributions made by the eletric field and magnetic field components to the intensity of an `EM` wave is.

Options

A. `C:1`
B. `C^(2):1`
C. `1:1`
D. `sqrt(C:1)`

Explanation

To find the ratio of contributions made by the electric field and magnetic field components to the intensity of an electromagnetic (EM) wave, we can follow these steps:

### Step 1: Understand the Intensity of an EM Wave
The intensity \( I \) of an electromagnetic wave is given by the formula:
\[ I = \frac{U_{\text{average}}}{t} \]
where \( U_{\text{average}} \) is the average energy density of the wave.

### Step 2: Energy Density Contributions
The energy density contributions from the electric field \( (U_E) \) and the magnetic field \( (U_B) \) can be expressed as:
- For the electric field:
\[ U_E = \frac{1}{2} \epsilon_0 E_0^2 \]
- For the magnetic field:
\[ U_B = \frac{1}{2} \frac{B_0^2}{\mu_0} \]

### Step 3: Relate Electric and Magnetic Fields
In an electromagnetic wave, the electric field \( E_0 \) and the magnetic field \( B_0 \) are related by the equation:
\[ E_0 = c B_0 \]
where \( c \) is the speed of light in vacuum, given by \( c = \frac{1}{\sqrt{\mu_0 \epsilon_0}} \).

### Step 4: Substitute \( E_0 \) in Energy Density
Substituting \( E_0 = c B_0 \) into the expression for \( U_E \):
\[ U_E = \frac{1}{2} \epsilon_0 (c B_0)^2 = \frac{1}{2} \epsilon_0 c^2 B_0^2 \]
Since \( c^2 = \frac{1}{\mu_0 \epsilon_0} \), we can substitute this into the equation:
\[ U_E = \frac{1}{2} \epsilon_0 \left(\frac{1}{\mu_0 \epsilon_0}\right) B_0^2 = \frac{1}{2} \frac{B_0^2}{\mu_0} \]

### Step 5: Compare Energy Densities
Now we have:
- \( U_E = \frac{1}{2} \frac{B_0^2}{\mu_0} \)
- \( U_B = \frac{1}{2} \frac{B_0^2}{\mu_0} \)

### Step 6: Calculate the Ratio
The ratio of contributions made by the electric field to the magnetic field is:
\[ \text{Ratio} = \frac{U_E}{U_B} = \frac{\frac{1}{2} \frac{B_0^2}{\mu_0}}{\frac{1}{2} \frac{B_0^2}{\mu_0}} = 1 \]

### Conclusion
Thus, the ratio of contributions made by the electric field and magnetic field components to the intensity of an EM wave is:
\[ \text{Ratio} = 1:1 \]

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