A charged particle oscillates about its mean equilibrium position with a frerquency of `10^9 H_z`. The electromagnetic waves produced.

Options

A. will have frequency of `10^(9)` Hz
B. will have frequency of `2xx 10^(9)` Hz
C. will have wavelength of 0.3 m
D. fall in the region of radiowaves

Explanation

To solve the problem regarding the electromagnetic waves produced by a charged particle oscillating about its mean equilibrium position with a frequency of \(10^9 \, \text{Hz}\), we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Oscillation of the Charged Particle**:
- A charged particle oscillating means it is moving back and forth around a central point (equilibrium position). The frequency of this oscillation is given as \(f = 10^9 \, \text{Hz}\).

2. **Relation Between Charged Particle and Electromagnetic Waves**:
- When a charged particle oscillates, it produces electromagnetic waves. The frequency of these electromagnetic waves is directly related to the frequency of the oscillation of the charged particle.

3. **Determining the Frequency of the Electromagnetic Waves**:
- Since the frequency of the electromagnetic waves produced is the same as the frequency of the oscillating charged particle, we can state:
\[ f_{\text{EM waves}} = f_{\text{charged particle}} = 10^9 \, \text{Hz} \]

4. **Conclusion**:
- Therefore, the frequency of the electromagnetic waves produced by the charged particle oscillating at \(10^9 \, \text{Hz}\) is also \(10^9 \, \text{Hz}\).

### Final Answer:
The frequency of the electromagnetic waves produced is \(10^9 \, \text{Hz}\).

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