A car is moving with a constant speed of `60 km h^-1` on a straight road. Looking at the rear view mirror, the driver finds that the car following him is at a distance of `100 m` and is approaching with a speed of `5 km h^-1`. In order to keep track of the car in the rear, the driver begins to glane alternatively at the rear and side mirror of his car after every `2 s` till the other car overtakes. If the two cars were maintaining their speeds, which of the following statement (s) is/are correct ?

Options

A. The speed of car in the rear is `65 km//h^(-1)`
B. In the side mirror, the car in the rear would appear to approach with a speed of `5 kmh^(-1)` to the driver of the leading car
C. In the rear view mirror, the speed of the approaching car would appear to decrease as the distance between the cars decreases
D. In the side mirror, the speed of the approaching car would appear to increases as the distance between the cars decreases

Explanation

To solve the problem, we need to analyze the situation step by step, considering the speeds of both cars and how they relate to the mirrors used by the driver.

### Step 1: Understand the speeds of the cars
- The driver’s car is moving at a speed of \(60 \text{ km/h}\).
- The following car is approaching at a speed of \(5 \text{ km/h}\).

### Step 2: Convert speeds to meters per second
To make calculations easier, we convert the speeds from km/h to m/s:
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