Three immiscible liquids of densities `d_1 gt d_2 gt d_3` and refractive indices `mu_1 gt mu_2 gt mu_3` are put in a beaker. The height of each liquid column is `(h)/(3)`. A dot is made at the bottom of the beaker. For near normal vision, find the apparent depth of the dot.

Explanation

To find the apparent depth of the dot at the bottom of the beaker containing three immiscible liquids with different densities and refractive indices, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Setup**:
- We have three immiscible liquids with densities \( d_1 > d_2 > d_3 \) and refractive indices \( \mu_1 > \mu_2 > \mu_3 \).
- Each liquid has a height of \( \frac{h}{3} \).

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