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In figure , assuming the diodes to be id...

In figure , assuming the diodes to be ideal ,

A

`D_(1)` is forward biased and `D_(2)` is reverse biased and hence current flows from A to B

B

`D_(2)` is forward biased and `D_(1)` is reverse biased and hence no current flows from B to A and vice-versa.

C

`D_(1) " and " D_(2)` are both forward biased and hence current flows from A to B

D

`D_(1) " and " D_(2)` are both reverse biased and hence no current flows from A to B and vice-verse.

Text Solution

Verified by Experts

The correct Answer is:
B
In the given circuit `p-`side of `p - n` function `D_(1)` is connected to lower voltage and `n-`side of `D_(1)` to higher voltage. Thus D is reverse blased.
The `p-`side of `p -n` junction `D_(2)` is at higher potential and `n-`side of `D_(2)` is at lower potential.
Therefore `D_(2)` is forward blassed
Hence, current flows through the junction B to A
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