In a `n - p - n` transistor circuit, the collector current is `10 mA`. If 95 per cent of the electrons emitted reach the collector, which of the following statements are true ?

Options

A. The emitter current will be `8 mA`
B. The emitter current will be `10.53 mA`
C. The base current will be `0.53 mA`
D. The base current will be `2 mA`

Explanation

To solve the problem step by step, we will analyze the given information about the NPN transistor circuit and derive the necessary values.

### Step 1: Understand the relationship between the currents in the transistor.
In a transistor, the relationship between the emitter current (I_E), collector current (I_C), and base current (I_B) is given by the equation:
\[ I_E = I_B + I_C \]

### Step 2: Identify the given values.
From the problem, we know:
- The collector current \( I_C = 10 \, \text{mA} \)
- 95% of the electrons emitted reach the collector.

### Step 3: Calculate the emitter current (I_E).
Since 95% of the emitted electrons reach the collector, we can express this as:
\[ I_C = 0.95 \times I_E \]
Rearranging this gives:
\[ I_E = \frac{I_C}{0.95} \]

Substituting the value of \( I_C \):
\[ I_E = \frac{10 \, \text{mA}}{0.95} \]

Calculating this:
\[ I_E \approx 10.53 \, \text{mA} \]

### Step 4: Calculate the base current (I_B).
Now that we have \( I_E \), we can find \( I_B \) using the relationship from Step 1:
\[ I_B = I_E - I_C \]
Substituting the values we found:
\[ I_B = 10.53 \, \text{mA} - 10 \, \text{mA} \]
\[ I_B \approx 0.53 \, \text{mA} \]

### Step 5: Conclusion.
Now we have calculated:
- Emitter current \( I_E \approx 10.53 \, \text{mA} \)
- Base current \( I_B \approx 0.53 \, \text{mA} \)

### True Statements:
Based on the calculations:
- The emitter current is approximately 10.53 mA.
- The base current is approximately 0.53 mA.