Three photodiodes `D_1 , D_2 ` and `D_3` are made of semiconductors having
band gaps of ` 2.5 eV , 2 eV` and 3 eV , respectively . Which one will be able to detect light of wavelength ` 6000 Å ` ?

Explanation

To determine which photodiode can detect light of wavelength 6000 Å (or 6000 x 10^-10 meters), we need to compare the energy of the incident light with the band gap energies of the photodiodes. The energy of a photon can be calculated using the formula:

\[ E = \frac{hc}{\lambda} \]

where:
- \(E\) is the energy of the photon,
...