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A piece of wood form the ruins of an an...

A piece of wood form the ruins of an ancient building was found to have a `C^(14)` activity of 12 disintegrations per minute per gram of its carbon content. The `C^(14)` activity of the living wood is 16 disintegrations/minute/gram. How long ago did the trees, from which the wooden sample came, die? Given half-life of `C^(14)` is 5760 years.

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To determine how long ago the trees from which the wooden sample came died, we can use the information provided about the activity of Carbon-14 (`C^(14)`) and its half-life. Here’s a step-by-step solution: ### Step 1: Understand the given data - Current activity of the wood sample (`A_t`): 12 disintegrations/minute/gram - Initial activity of living wood (`A_0`): 16 disintegrations/minute/gram - Half-life of `C^(14)` (`t_half`): 5760 years ### Step 2: Calculate the decay constant (λ) ...
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Determine the average .^(14)C activity in decays per minute per gram of natural carbon found in living organisms if the concentration of .^(14)C relative to that of .^(12)C is 1.4 xx10^(-12) and half -life of .^(14)C is T_(1//2)=57.30 years.

A piece of wood was found to have C^(14)//C^(12) ratio 0.6 times that in a living plant. Calculate that in a living plant. Calculate the period when the plant died. (Half life of C^(14) = 5760 years)?

A 25 g piece of characoal is found in some ruins of an ancient city. The sample shows a C^(14) activity of 250 decay/minutes. How long has the three this charcoal came from been dead ? Given, the half-life of C^(14) is 5730 years. The ratio of C^(14) and C^(12) in the living sample is 1.3 xx 10^(-12) .

A piece of wood from an archaeological source shows a .^(14)C activity which is 60% of the activity found in fresh wood today. Calculate the age of the archaeological sample. ( t_(1//2) for .^(14)C = 5570 year)

Half - life period of ""^(14)C is 5770 years . If and old wooden toy has 0.25% of activity of ""^(14)C Calculate the age of toy. Fresh wood has 2% activity of ""^(14)C .

Carbon -14 used to determine the age of organic material. The procedure is absed on the formation of C^(14) by neutron capture iin the upper atmosphere. ._(7)N^(14)+._(0)n^(1) rarr ._(6)C^(14)+._(1)H^(1) C^(14) is absorbed by living organisms during photosynthesis. The C^(14) content is constant in living organism. Once the plant or animal dies, the uptake of carbon dioxide by it ceases and the level of C^(14) in the dead being falls due to the decay, which C^(14) undergoes. ._(6)C^(14)rarr ._(7)N^(14)+beta^(c-) The half - life period of C^(14) is 5770 year. The decay constant (lambda) can be calculated by using the following formuls : lambda=(0.693)/(t_(1//2)) The comparison of the beta^(c-) activity of the dead matter with that of the carbon still in circulation enables measurement of the period of the isolation of the material from the living cycle. The method, however, ceases to be accurate over periods longer than 30000 years. The proportion of C^(14) to C^(12) in living matter is 1:10^(12) . A nuclear explosion has taken place leading to an increase in the concentration of C^(14) in nearby areas. C^(14) concentration is C_(1) in nearby areas and C_(2) in areas far away. If the age of the fossil is determined to be T_(1) and T_(2) at the places , respectively, then

Carbon -14 used to determine the age of organic material. The procedure is absed on the formation of C^(14) by neutron capture iin the upper atmosphere. ._(7)N^(14)+._(0)n^(1) rarr ._(6)C^(14)+._(1)H^(1) C^(14) is absorbed by living organisms during photosynthesis. The C^(14) content is constant in living organism. Once the plant or animal dies, the uptake of carbon dioxide by it ceases and the level of C^(14) in the dead being falls due to the decay, which C^(14) undergoes. ._(6)C^(14)rarr ._(7)N^(14)+beta^(c-) The half - life period of C^(14) is 5770 year. The decay constant (lambda) can be calculated by using the following formuls : lambda=(0.693)/(t_(1//2)) The comparison of the beta^(c-) activity of the dead matter with that of the carbon still in circulation enables measurement of the period of the isolation of the material from the living cycle. The method, however, ceases to be accurate over periods longer than 30000 years. The proportion of C^(14) to C^(12) in living matter is 1:10^(12) . What should be the age of fossil for meaningful determination of its age ?

(a) Determine the number of carbon ._6^(14)C atoms present for every gram of carbon ._6^(12)C in a living organism. Find (b) The decay constatnt and (c ) the activity of this sample.

A wooden artifact sample gave activity 32-beta particles per second while the freshly cut wood gave activity of 64 beta particles per second in Geiger Muller counter. Calculate the age of the wooden artifact (t_(1//2) "of" C^(14) = 5760 years)

What is the age of an ancient wooden piece if it is known that the specific activity of C^(14) nuclide in it amouts to 3//5 of that in fresh trees? Given: the half of C nuclide is 5570 years and log_(e)(5//3)=0.5 .

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