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A TV transmission tower has a height of ...

A TV transmission tower has a height of 240 m. Signals broadcast from this tower will be received by LOS communication at a distance of (assume the radius of earth to be `6.4 xx 10 ^(6) m`)

A

100 km

B

24 km

C

55 km

D

50 km

Text Solution

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The correct Answer is:
To solve the problem of determining the maximum distance for Line of Sight (LOS) communication from a TV transmission tower of height 240 m, we can use the formula for the distance \( D \) that can be covered by LOS communication: \[ D = \sqrt{2 \cdot R \cdot H} \] Where: - \( D \) is the distance in meters, - \( R \) is the radius of the Earth (given as \( 6.4 \times 10^6 \) m), - \( H \) is the height of the tower (given as 240 m). ### Step 1: Substitute the values into the formula We start by substituting the values of \( R \) and \( H \) into the formula: \[ D = \sqrt{2 \cdot (6.4 \times 10^6) \cdot 240} \] ### Step 2: Calculate the product inside the square root Now, we calculate the product: \[ 2 \cdot (6.4 \times 10^6) \cdot 240 \] Calculating \( 2 \cdot 6.4 = 12.8 \), then: \[ 12.8 \cdot 240 = 3072 \] Thus, we have: \[ D = \sqrt{3072 \times 10^6} \] ### Step 3: Calculate the square root Now we calculate the square root: \[ D = \sqrt{3072} \times 10^3 \] Calculating \( \sqrt{3072} \): \[ \sqrt{3072} \approx 55.4 \] Thus, we have: \[ D \approx 55.4 \times 10^3 \text{ m} \] ### Step 4: Convert meters to kilometers To convert meters to kilometers, we divide by 1000: \[ D \approx 55.4 \text{ km} \] ### Conclusion The maximum distance for LOS communication from the TV transmission tower is approximately 55.4 km. Therefore, the correct option is 55 km. ---

To solve the problem of determining the maximum distance for Line of Sight (LOS) communication from a TV transmission tower of height 240 m, we can use the formula for the distance \( D \) that can be covered by LOS communication: \[ D = \sqrt{2 \cdot R \cdot H} \] Where: - \( D \) is the distance in meters, ...
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