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The gravitational force between two obje...

The gravitational force between two object is F. It masses of both object are halved without changing distance between them, then the gravitation force would become

A

F/4

B

F/2

C

F

D

2F

Text Solution

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The correct Answer is:
To solve the problem, we need to understand how the gravitational force between two masses changes when the masses are halved. The gravitational force \( F \) between two objects is given by the formula: \[ F = \frac{G \cdot m_1 \cdot m_2}{r^2} \] where: - \( F \) is the gravitational force, - \( G \) is the gravitational constant, - \( m_1 \) and \( m_2 \) are the masses of the two objects, - \( r \) is the distance between the centers of the two masses. ### Step 1: Write down the initial gravitational force The initial gravitational force between the two masses is given by: \[ F = \frac{G \cdot m_1 \cdot m_2}{r^2} \] ### Step 2: Halve the masses According to the problem, both masses are halved. Therefore, the new masses will be: \[ m_1' = \frac{m_1}{2} \quad \text{and} \quad m_2' = \frac{m_2}{2} \] ### Step 3: Write down the new gravitational force Now, we need to find the new gravitational force \( F' \) when the masses are halved. The new gravitational force can be expressed as: \[ F' = \frac{G \cdot m_1' \cdot m_2'}{r^2} \] Substituting the new masses into the equation: \[ F' = \frac{G \cdot \left(\frac{m_1}{2}\right) \cdot \left(\frac{m_2}{2}\right)}{r^2} \] ### Step 4: Simplify the new force equation Now, simplify the equation: \[ F' = \frac{G \cdot \frac{m_1 \cdot m_2}{4}}{r^2} \] This can be rewritten as: \[ F' = \frac{1}{4} \cdot \frac{G \cdot m_1 \cdot m_2}{r^2} \] ### Step 5: Substitute the initial force Since we know that \( F = \frac{G \cdot m_1 \cdot m_2}{r^2} \), we can substitute this into our equation for \( F' \): \[ F' = \frac{1}{4} F \] ### Conclusion Thus, the new gravitational force when both masses are halved is: \[ F' = \frac{F}{4} \] ### Final Answer The gravitational force would become \( \frac{F}{4} \). ---

To solve the problem, we need to understand how the gravitational force between two masses changes when the masses are halved. The gravitational force \( F \) between two objects is given by the formula: \[ F = \frac{G \cdot m_1 \cdot m_2}{r^2} \] where: - \( F \) is the gravitational force, ...
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Knowledge Check

  • The gravitational force between two bodies is :

    A
    always repulsive
    B
    always attractive
    C
    attractive only at large distances
    D
    repulsive only at large distances.
  • The gravitational force between two stones of mass 1 kg each separted by a distance of 1 metre in vaccum is

    A
    zero
    B
    `6.675 xx 10^(-5)` newton
    C
    `6.675 xx 10^(-11)` newton
    D
    `6.75 xx 10^(-8)` newton
  • Two sphere of masses m and M are situated in air and the gravitational force between them is F . The space around the masses in now filled with a liquid of specific gravity 3 . The gravitational force will now be

    A
    3F
    B
    F
    C
    `(F)/(3)`
    D
    `(F)/(9)`
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