A girl is carrying a school bag of 3 kg mass on her back and moves 200 m on a lavelled road. The wrok done against the gracitational force will be `(g=10ms^(2))`

Options

A. `6xx10^(3)J`
B. `6J`
C. `0.6J`
D. zero

Explanation

To solve the problem of calculating the work done against the gravitational force while the girl carries her school bag, we can follow these steps:

### Step 1: Identify the forces acting on the bag
The only force acting against the gravitational force is the weight of the bag. The weight (W) can be calculated using the formula:
\[ W = m \cdot g \]
where:
- \( m = 3 \, \text{kg} \) (mass of the bag)
- \( g = 10 \, \text{m/s}^2 \) (acceleration due to gravity)

### Step 2: Calculate the weight of the bag
Substituting the values into the formula:
\[ W = 3 \, \text{kg} \cdot 10 \, \text{m/s}^2 = 30 \, \text{N} \]
So, the weight of the bag is 30 N.

### Step 3: Determine the direction of movement and the angle
The girl is moving horizontally on a leveled road, while the gravitational force acts vertically downward. Therefore, the angle (\( \theta \)) between the gravitational force and the direction of displacement is 90 degrees.

### Step 4: Use the work done formula
The work done (W) against a force can be calculated using the formula:
\[ W = F \cdot D \cdot \cos(\theta) \]
where:
- \( F \) is the force (weight of the bag, 30 N)
- \( D \) is the distance moved (200 m)
- \( \theta \) is the angle between the force and the direction of movement (90 degrees)

### Step 5: Calculate the work done
Substituting the values into the work done formula:
\[ W = 30 \, \text{N} \cdot 200 \, \text{m} \cdot \cos(90^\circ) \]
Since \( \cos(90^\circ) = 0 \):
\[ W = 30 \, \text{N} \cdot 200 \, \text{m} \cdot 0 = 0 \]

### Conclusion
The work done against the gravitational force while the girl moves 200 m on a leveled road is **0 Joules**.

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