A ball is dropped from a height of 10 m. If the energy of the ball reduces by 40% after striking the ground, how much high can the ball bounce back ? `(g = 10m//s^2)`

Explanation

If the energy of the ball reduces by 40% after striking the ground, then remaining energy of the ball will be 60% of initial energy.
Let initial energy of the body of mass (m) at height (h) is (mgh).
According to the question, `"60% of mgh" " "["given,"h=10and g=10ms^(-2)]`
`h'=60%xxh(60)/(100)xx10=6m`