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An element is placed in 2^("nd") group a...

An element is placed in `2^("nd")` group and `3^("rd")` period of the periodic table, burns is presence of xygen of form a basic oxide
(a) Identify the element
(b) Write the electronic configuration
(c) Write a balanced equation when it burns in the presence of air
(d) Write a balanced when this oxide is dissolved in water
(e) Draw the electron dot structure for the formation of this oxide.

Text Solution

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(a) Since, the element lies in group 2, it must be an alkaline earth metal. Since, it lies in the third period, it must be magnesium (Mg)
(b) Atomic number of Mg is 12, therefore, its electronic configuration is : `underset(2)(K)underset(8)(L)underset(2)(M)`
(c) When Mg burns in the presence of air it forms a basic oxide, MgO
`underset("Magnesium")(2Mg(s))+underset("Oxygen")(O_(2)(g))overset("Heat")(rarr)underset("Magnesium oxide")(2MgO(s))`
(d) When MgO is dissolved in water it forms magnesium hydroxide
`underset("Magnesium oxide")(2MgO(s))+underset("Water")(2H_(2)O(l))rarrunderset("Magnesium hydroxide")(2Mg(OH)_(2)(aq))`
(e) Mg has 2 valence electrons [as electronic configuration of `._(12)Mg = 2,8,2`] oxygen has 6 valence electron [as electronic configuration of `._(8)O=2,6`]
Electron dot structure for the formation of magnesium oxide
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