An unsaturated hydrocarbon 'A' adds two molecules of `H_(2)` and on reductive ozonolysis gives butane-1, 4-dial, ethanal and propanone. Give the structure of 'A' , write its IUPAC name and explain the reactions involved.

Explanation

To solve the problem, we need to identify the structure of the unsaturated hydrocarbon 'A', determine its IUPAC name, and explain the reactions involved in producing the given products.

### Step 1: Understanding the Reaction
The problem states that the unsaturated hydrocarbon 'A' adds two molecules of \( H_2 \). This indicates that 'A' is likely either an alkyne (which contains a triple bond) or an alkadiene (which contains two double bonds). Since the ozonolysis of 'A' yields three different products, it suggests that 'A' is an alkadiene, as it can break down into three compounds.

### Step 2: Identifying the Products
The products of the ozonolysis are:
1. Butane-1,4-dial (which has the structure \( CHO-CH_2-CH_2-CHO \))
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