Atmospheric pressure recorded in different citie are as follows
`{:("Cities","Shimla","Bangalore","Delhi","Mumbai"),("p in "N//m^(2),1.01xx10^(5),1.2 xx 10^(5),1.02 xx 10^(5),1.21 xx 10^(5)):}`
Consider the above data mark the place at which liquid will boil first.

Options

A. Shimla
B. Bangalore
C. Delhi
D. Mumbai

Explanation

To determine at which location a liquid will boil first based on the given atmospheric pressures, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Relationship Between Boiling Point and Atmospheric Pressure:**
- The boiling point of a liquid is the temperature at which its vapor pressure equals the atmospheric pressure. Therefore, the lower the atmospheric pressure, the lower the temperature required for the liquid to boil.

2. **List the Atmospheric Pressures:**
- From the data provided:
- Shimla: \(1.01 \times 10^5 \, \text{N/m}^2\)
- Bangalore: \(1.2 \times 10^5 \, \text{N/m}^2\)
- Delhi: \(1.02 \times 10^5 \, \text{N/m}^2\)
- Mumbai: \(1.21 \times 10^5 \, \text{N/m}^2\)

3. **Identify the Lowest Atmospheric Pressure:**
- Compare the atmospheric pressures:
- Shimla: \(1.01 \times 10^5 \, \text{N/m}^2\)
- Bangalore: \(1.2 \times 10^5 \, \text{N/m}^2\)
- Delhi: \(1.02 \times 10^5 \, \text{N/m}^2\)
- Mumbai: \(1.21 \times 10^5 \, \text{N/m}^2\)
- The lowest atmospheric pressure is in Shimla at \(1.01 \times 10^5 \, \text{N/m}^2\).

4. **Conclusion:**
- Since Shimla has the lowest atmospheric pressure, the liquid will boil first in Shimla.

### Final Answer:
The liquid will boil first in **Shimla**.

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