The average velocity of `CO_(2)` at the temperature `T_(1)K` and maximum (most) proable velocity of `CO_(2)` at the temperature `T_(2) K` is `9xx10^(4) cm s^(-1)`. Calculate the values of `T_(1)` and `T_(2)`.

Explanation

To solve the problem, we need to calculate the temperatures \( T_1 \) and \( T_2 \) based on the given velocities of \( CO_2 \).

### Step-by-Step Solution:

1. **Understanding the Given Information**:
- The average velocity of \( CO_2 \) at temperature \( T_1 \) is given.
- The maximum (most probable) velocity of \( CO_2 \) at temperature \( T_2 \) is also given.
- Both velocities are equal to \( 9 \times 10^4 \) cm/s.
...