Carbon dioxide unusual because it has no liquid phase at normal atmospheric pressure. Instead, the solid sublimes directly to the gas phase. To obtain the liquid phase at room temperature, a pressuer of _____`MP` a must be applied.
Carbon dioxide unusual because it has no liquid phase at normal atmospheric pressure. Instead, the solid sublimes directly to the gas phase. To obtain the liquid phase at room temperature, a pressuer of _____`MP` a must be applied.
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AI Generated Solution
To solve the question regarding the pressure required to obtain the liquid phase of carbon dioxide (CO₂) at room temperature, we can follow these steps:
### Step-by-Step Solution:
1. **Understanding Sublimation**:
- Carbon dioxide sublimates, which means it transitions directly from the solid phase to the gas phase without passing through a liquid phase at normal atmospheric pressure.
2. **Identifying the Conditions**:
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Answer the following questions based on the p-T phase diagram of carbon dioxide as shown in the figure . (i) At what temperature and pressure can the solid , liquid and vapour phases of C0_(2) co-exist in equilibrium? (ii) What is the effect of decrease of pressure on the fusion and boiling point of C0_(2) ? (iii) What are the critical temperature and pressure for C0_(2) ? what is their significance ? (iv) Is C0_(2) solid , liquid, or gas at (a) -70^(@)C under 1 atm (b) -60^(@)C under 10 atm (c) 15^(@)C under 56 atm ?
Answer the following questions based on the p-T phase diagram of carbon dioxide as shown in the figure . (i) At what temperature and pressure can the solid , liquid and vapour phases of C0_(2) co-exist in equilibrium? (ii) What is the effect of decrease of pressure on the fusion and boiling point of C0_(2) ? (iii) What are the critical temperature and pressure for C0_(2) ? what is their significance ? (iv) Is C0_(2) solid , liquid, or gas at (a) -70^(@)C under 1 atm (b) -60^(@)C under 10 atm (c) 15^(@)C under 56 atm ?
In a constant volume gas thermometer, the pressure of the working gas is measured by the difference in the levels of mercury in the two arms of a U-tube connected to the gas at one end. When the bulb is placed at the room temperature 27.0^0 C , the mercury column in the arm open to atmosphere stands 5.00 cm above the level of mercury in the other arm. When the bulb is placed in a hot liquid, the difference of mercury levels becomes 45.0 cm . Calculate the temperature of the liquid. (Atmospheric pressure = 75.0cm of mercury).
In a constant volume gas thermometer, the pressure of the working gas is measured by the differenced in the levels of mercury in the two arms of a U-tube connected to the gas at one end. When the bulb is placed at the room temperature 27.0^0 C , the mercury column in the arm open to atmosphere stands 5.00 cm above the level of mercury in the other arm. When the bulb is placed in a hot liquid, the difference of mercury levels becomes 45..0 Cm . Calculate the temperature of the liquid. (Atmospheric pressure = 75.0cm of mercury).
Each phase of a material can exits only in certain regions of pressure and temperature . P-T phase diagrams, in which pressure is plotted versus temperature, show the regions corresponding to various phases and phase transformations . P-V diagrams, on the other hand , can be used to study pressure volume relationship at a constant temperature. If the liquid and gaseous phases of a pure substances are heated together in a closed container, both the temperature and the vapor pressure will increase until a point is reached at which the two phases can no longer be distinguished from one another. The temperature and pressure at which this occurs are called the critical temperature and pressure. Exceeding either of these parameters, by itself ,will cause the "gas"//"liguid" phase transition to disappear. if the other variable is then changed as well, while the first variable is maintained above its critical point , a gradual transition will occur between the gaseous and liquid phases, with no clear boundary.(The liquid and solid phases, on the other hand , maintain a distinct boundary at all pressure above the triple point). Shown in figure is a combined P-T phase diagram for material A and B . If heat is added to solids A and B , each in a container that is open to the atmosphere :-
Each phase of a material can exits only in certain regions of pressure and temperature . P-T phase diagrams, in which pressure is plotted versus temperature, show the regions corresponding to various phases and phase transformations . P-V diagrams, on the other hand , can be used to study pressure volume relationship at a constant temperature. If the liquid and gaseous phases of a pure substances are heated together in a closed container, both the temperature and the vapor pressure will increase until a point is reached at which the two phases can no longer be distinguished from one another. The temperature and pressure at which this occurs are called the critical temperature and pressure. Exceeding either of these parameters, by itself ,will cause the "gas"//"liguid" phase transition to disappear. if the other variable is then changed as well, while the first variable is maintained above its critical point , a gradual transition will occur between the gaseous and liquid phases, with no clear boundary.(The liquid and solid phases, on the other hand , maintain a distinct boundary at all pressure above the triple point). Shown in figure is a combined P-T phase diagram for material A and B . Which is true about the substance in figure?
The concentration of a pure solid or liquid phase is not include in the expression of equilibrium constant because :
The pressure of two pure liquid A and B which form an ideal solutions are 400 mm Hg and 800 mm Hg respectively at temperature T.A liquid containing 3:1 molar composition pressure can be varied.The solutions is slowly vapourized at temperature T by decreasing the applied pressure starting with a pressure of 760 mm Hg.A pressure gauge (in mm) Hg is connected which give the reading of pressure applied. The reading of pressure Gauge at which only liquid phase exists.
Answer the following questions based on the P – T phase diagram of CO_(2) : (a) CO_(2) at 1 atm pressure and temperature – 60^(@)C is compressed isothermally. Does it go through a liquid phase ? (b) What happens when CO_(2) at 4 atm pressure is cooled from room temperature at constant pressure ? (c) Describe qualitatively the changes in a given mass of solid CO_(2) at 10 atm pressure and temperature –65^(@)C as it is heated up to room temperature at constant pressure. (d) CO_(2) is heated to a temperature 70^(@)C and compressed isothermally. What changes in its properties do you expect to observe ?
The pressure of two pure liquid A and B which form an ideal solutions are 400 mm Hg and 800 mm Hg respectively at temperature T.A liquid containing 3:1 molar composition pressure can be varied.The solutions is slowly vapourized at temperature T by decreasing the applied pressure starting with a pressure of 760 mm Hg.A pressure gauge (in mm) Hg is connected which give the reading of pressure applied. The reading of pressure Gauge at which only vapour phase exists is
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