If the perpendicular distance of a point P from the X-axis is 5 units and the foot of the perpendicular lies on the negative direction of X-axis then the point P has

Options

A. x-coordinate =-5
B. y-coordinate =5 only
C. y-coordiante=-5 only
D. y-coordinate =5 or -5

Explanation

To solve the problem, we need to determine the coordinates of point P based on the given conditions.

### Step-by-Step Solution:

1. **Understanding the Problem**: We know that point P has a perpendicular distance of 5 units from the X-axis. The foot of the perpendicular lies on the negative direction of the X-axis.

2. **Identifying the Y-coordinate**: The distance of a point from the X-axis is represented by its Y-coordinate. Since the distance is 5 units, the Y-coordinate can either be +5 or -5. This means point P could be either above the X-axis (Y = 5) or below the X-axis (Y = -5).

3. **Identifying the X-coordinate**: The problem states that the foot of the perpendicular lies on the negative direction of the X-axis. This means that the X-coordinate of the foot of the perpendicular (and thus the X-coordinate of point P) must be negative.

4. **Conclusion**: Therefore, the coordinates of point P can be represented as:
- If P is above the X-axis: P = (x, 5) where x < 0
- If P is below the X-axis: P = (x, -5) where x < 0

5. **Final Answer**: The point P has coordinates of the form (x, 5) or (x, -5) where x is a negative number.