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In the adjoining figure , we have AC=DC...

In the adjoining figure , we have AC=DC and CB = CE. Show that AB=DE.

Text Solution

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Given, AC=DC …(i)
and CB=CE …(ii)
According to Euclid's axiom , if equals are added to equals , then wholes are also equal. So . On adding Eqs. (i) and (ii), we get
AC+CB=DC+CE
`rArr` AB=DE
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