The position of Br in the compound in `CH_(2)=CHC(Br)(CH_(3))_(2)` can be classified as……..

Options

A. allyl
B. aryl
C. vinyl
D. secondary

Explanation

To determine the classification of the position of Br in the compound \( CH_2=CHC(Br)(CH_3)_2 \), we will follow these steps:

### Step 1: Draw the Structure of the Compound
The first step is to visualize the structure of the compound. The given compound can be broken down as follows:
- \( CH_2=CH \) indicates a double bond between two carbon atoms.
- \( C(Br)(CH_3)_2 \) indicates that the next carbon (attached to the double bond) has a bromine (Br) and two methyl groups (CH3) attached to it.

The structure can be drawn as:
```
CH3
|
CH2 = CH - C(Br) - CH3
```

### Step 2: Identify the Carbon Atom to Which Br is Attached
In the drawn structure, the carbon atom that is bonded to Br is also bonded to two CH3 groups and is part of the double bond with the adjacent carbon. This carbon is the central carbon in the structure.

### Step 3: Classify the Position of Br
To classify the position of Br, we need to determine whether the carbon atom to which Br is attached is a primary, secondary, or tertiary carbon:
- **Primary (1°)**: A carbon atom bonded to one other carbon atom.
- **Secondary (2°)**: A carbon atom bonded to two other carbon atoms.
- **Tertiary (3°)**: A carbon atom bonded to three other carbon atoms.

In our case, the carbon atom bonded to Br is attached to:
- Two CH3 groups (2 carbon atoms)
- One carbon atom from the double bond (1 carbon atom)

Thus, the central carbon has a total of three carbon atoms attached to it (two from the methyl groups and one from the double bond).

### Conclusion
Since the carbon atom to which Br is attached is bonded to three other carbon atoms, it is classified as a **tertiary carbon**. Therefore, the position of Br in the compound \( CH_2=CHC(Br)(CH_3)_2 \) can be classified as **tertiary**.

### Final Answer
The position of Br in the compound \( CH_2=CHC(Br)(CH_3)_2 \) can be classified as **tertiary**.

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